#include<cstdio>
int main(){
	int n,m;
	while(scanf("%d%d",&n,&m)!=EOF){
		int i=1;
		for(i;(i+m)<=n;i+=m)
			printf("%d ",2*i+m-1);
		printf("%d\n",2*i+n-i);
	}
}
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Followed by:

• Re:10行C代碼，超簡單 (256)  DouglasLT 2019-03-15 15:13:43 Problem 2015
  • Re:10行C代碼，超簡單 (991)  18-大數據-杜廣華 2019-03-23 12:50:02
  • Re:10行C代碼，超簡單 (172)  seewill 2019-10-13 10:45:39
  • Re:10行C代碼，超簡單 (0)  wh0121910870420 2019-11-02 09:59:30
  • Re:10行C代碼，超簡單 (0)  fuzhuzhu 2020-09-09 17:56:51

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